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Find the smallest number that, when divided by 8, 10, 20, and 30, leaves a remainder of 5 in each case.
  1. 120
  2. 125
  3. 240
  4. None of these
Explanation

LCM of 8, 10, 20, and 30 = 120.

Required number = LCM + remainder

= 120 + 5

= 125


Last verified on 09-10-2026

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