A box contains 5 red, 4 blue, and 3 green balls. Two balls are drawn without replacement. What is the probability that both balls are blue?
- 1/11
- 1/6
- 3/11
- None of these
Explanation
Total balls = 5 red + 4 blue + 3 green = 12 balls
Number of blue balls = 4
We need probability that both balls drawn are blue, without replacement.
First ball blue = 4/12
Second ball blue = 3/11
Multiply them: (4/12) * (3/11) = 12/132 = 1/11
Last verified on 21-08-2016
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