Three dice (each having six faces with each face having one number from 1 to 6) are rolled. What is the number of possible outcomes such that at least one dice shows the number 2?
- 36
- 81
- 91
- 116
Explanation
91
Hence, total number of ways =(3×5×5)+(3×5)+1=91.
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- 70
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- None of these
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- (-2A)^B
- -2A²B
- Both are equal
- Cannot be determined
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- 78
- 79
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- None of these
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