A 1000 kg vehicle is turning round a corner at 10 m/s as it travels along an arc of a circle, If the radius of the circular path is 10m, how large a force must be exerted by the pavement on the tyres to hold the vehicle in the circular path?
- 1.0 x 10^4 N
- 3.0 x 10^4 N
- 5.0 x 10^4 N
- 7.0 x 10^4 N
- 9.0 x 10^4 N
Explanation
To calculate the force exerted by the pavement on the tires, we can use the centripetal force formula:
Force (F) = (Mass (m) * Velocity squared (v^2)) / Radius (r)
Given:
Mass (m) = 1000 kg
Velocity (v) = 10 m/s
Radius (r) = 10 m
Calculate the centripetal force (F):
Using the formula, F = (m * v^2) / r, we can substitute the given values to find the force:
F = (1000 kg * (10 m/s)^2) / 10 m
F = 100,000 N / 1.0 x 10^4 N
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