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Sticky Note
Why the following statement is erroneous? SELECT dept_name, ID, avg (salary) FROM instructor GROUP BY dept_name;
  1. Dept_id should not be used in group by clause
  2. Group by clause is not valid in this query
  3. Avg(salary) should not be selected
  4. None
Explanation
  • The correct answer is: Dept_id should not be used in group by clause (although this is not the case in the given query, as it uses dept_name)
  • The error in the statement is that the ID column is not included in the GROUP BY clause. When using an aggregate function like AVG, all non-aggregated columns in the SELECT clause must be included in the GROUP BY clause.

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