Why the following statement is erroneous? SELECT dept_name, ID, avg (salary) FROM instructor GROUP BY dept_name;
- Dept_id should not be used in group by clause
- Group by clause is not valid in this query
- Avg(salary) should not be selected
- None
Explanation
- The correct answer is: Dept_id should not be used in group by clause (although this is not the case in the given query, as it uses dept_name)
- The error in the statement is that the ID column is not included in the GROUP BY clause. When using an aggregate function like AVG, all non-aggregated columns in the SELECT clause must be included in the GROUP BY clause.
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