Find the value of x when y = 5, if x varies directly as 4y-1 and x = 14 when y = 2?
- 35
- 38
- 28
- None of these
Explanation
Let z = 4y-1
When x = 14, y = 2, z = (4*2) – 1 = 7
Now, x varies directly as z = 4y-1
When y = 5, z = (4*5) – 1 = 19
x 14 7
y - 19
Therefore, x = (14*19)/7 = 38
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