Solve: X² + 18x + 81 = 0. What Is The Factor Form? - Testpoint

Testpoint Whatsapp group

Testpoint Whatsapp group

Solve: x² + 18x + 81 = 0. What is the factor form?

(x + 8)²
(x - 9)²
(x + 9)²
(x - 8)²

Explanation

$x^^{2} + 18 x + 81 = 0$ :

The first term is $x^^{2}$ , so $a = x$ .
The last term is $81$ , so $b^^{2} = 81$ , which means $b = 9$ (we take the positive root since the middle term is positive).
The middle term is $18 x$ . Let's check if it matches $2 ab$ : $2 (x) (9) = 18 x$ . It does.

Therefore, the quadratic expression $x^^{2} + 18 x + 81$ can be factored into $(x + 9)^^{2}$ .

So the factor form of the equation $x^^{2} + 18 x + 81 = 0$ is $(x + 9)^^{2} = 0$ .

Related MCQs

Convert 0.6% into a fraction.

3/500
3/50
6/100
6/500

اس سوال کو وضاحت کے ساتھ پڑھیں

What is the remainder when 9⁶+7 is divided by 8?

0
1
6
7

اس سوال کو وضاحت کے ساتھ پڑھیں

What is the remainder when 9⁶+7 is divided by 8?

0
1
6
7

اس سوال کو وضاحت کے ساتھ پڑھیں

Find the value of x: 27 : 72 :: x : 9 ?

3
3.375
4
4.5

اس سوال کو وضاحت کے ساتھ پڑھیں

Find the number which when added to itself 13 times, gives 112?

8
9
10
11

اس سوال کو وضاحت کے ساتھ پڑھیں

Test Point Whatsapp Channel

All Rights Reserved © TestPointpk.com