4^(2n+3) = 8^(n+5)?
- 9
- 7
- 8
- None of these
Explanation
Let's solve the equation:
4^(2n+3) = 8^(n+5)
Expressing both sides with base 2:
(2^2)^(2n+3) = (2^3)^(n+5)
2^(4n+6) = 2^(3n+15)
Equating exponents:
4n + 6 = 3n + 15
4n - 3n = 15 - 6
n = 9
Related MCQs
- 76,440
- 77,000
- 77,440
- 6050
اس سوال کو وضاحت کے ساتھ پڑھیں
- 15
- 35/2
- 25/2
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- ∛275
- 275²
- 275 ÷ 3
- None of these