Top Physics 1000 MCQs

Top Physics MCQs

چار آپشن میں سے کسی ایک پر کلک کرنے سے جواب سرخ ہو جائے گا۔

A convex lens of focal length 40 cm is in contact with a concave lens of focal length 25 cm. The power of the combination in diopters is?

-7.7
-1.5
-6.5
None of these

(0)

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Explanation

Convex lens: $f_{1} = + 0.40 m$
$P_{1} = \frac{1}{f_{1}} = \frac{1}{0.40} = + 2.5 D$
Concave lens: $f_{2} = - 0.25 m$
$P_{2} = \frac{1}{- 0.25} = - 4.0 D$

Step 2: Combined power

$P = P_{1} + P_{2} = + 2.5 + (- 4.0) = - 1.5 D$

The area near an electric charge within which it exerts force on another charged particle is called ______?

بجلی کے چارج کے قریب کا علاقہ جس کے اندر یہ کسی اور چارج شدہ ذرہ پر طاقت کا استعمال کرتا ہے اسے ______ کہا جاتا ہے؟

Source charge
Electric Field
Coulomb
None of these

(0)

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A system absorbs 80 J through heating while doing 100 J of work. What is the change in the internal energy of the system?

+18 J
-10 J
-20 J
None of these

(0)

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Explanation

We use the first law of thermodynamics:

$Δ U = Q - W$

where
$Q$ = heat absorbed by the system = $+ 80 J$
$W$ = work done by the system = $+ 100 J$

$Δ U = 80 - 100 = - 20 J$

An object that is moving with constant speed travels around a circular path. Which of the following is/are true concerning this motion? (i) The displacement is zero (ii) The average speed is zero (iii) The acceleration is zero

iii only
i only
i and iii only
None of these

(0)

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A light bulb has resistance of 150 Ω. Find the voltage while the current is 1.5 A?

225 V
250 V
22 V
None of these

(0)

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Explanation

Using Ohm’s law:

$V = I \times R$ $V = 1.5 \times 150$ $V = 225 V$

Find the time period of a simple pendulum whose length is 88.2 cm. The value of acceleration due to gravity is 9.8 m/s² at the place where experiment is performed?

4 sec
1.885 sec
1.233 sec
None of these

(0)

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Explanation

We use the formula for the time period of a simple pendulum:

$T = 2 π \sqrt{\frac{L}{g}}$

Given:
$L = 88.2 cm = 0.882 m$
$g = 9.8 {m/s}^{2}$

$T = 2 π \sqrt{\frac{0.882}{9.8}}$ $\frac{0.882}{9.8} = 0.09$ $\sqrt{0.09} = 0.3$ $T = 2 π \times 0.3 = 0.6 π$ $π \approx 3.1416 ⟹ T \approx 1.88496 s$

Which statement describes the electrical potential difference between two points in a wire carrying a current?

The ratio of the power dissipated between the points to the charge moved.
The force required to move a unit positive charge between the points.
The ratio of the energy dissipated between the points to the current.
None of the above

(0)

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A 100 kg man runs up a hill through a height of 4 m in seconds. How much work does he do against gravitational force?

5290 J
2060 J
3920 J
None of these

(0)

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Explanation

$W = m g h$ $W = 100 \times 9.8 \times 4$ $W = 3920 J$

An elevator, in which a man is standing, is moving upward with a constant speed of 10 m/s. If the man drops a coin from a height of 2.5m, find the time taken by it to reach the floor of the elevator g = 9.8 m/s².

0.502 sec
0.714 sec
0.707 sec
None of these

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Explanation

We already solved this:

Elevator moving at constant speed → in elevator’s frame, gravity is $g = 9.8 {m/s}^{2}$ downward.
Relative initial velocity = 0.
Distance = 2.5 m.

$2.5 = \frac{1}{2} (9.8) t^{2}$ $t^{2} = \frac{2.5}{4.9} = \frac{25}{49}$ $t = \frac{5}{7} \approx 0.714 s$

A body on a 20m high cliff drops a stone. One second later, he throws down another stone. Both the stones hit the ground simultaneously. Find the initial velocity of the second stone g = 10/sec².

30 m/s
10 m/s
15 m/s
None of these

(0)

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Explanation

Step 1: Time for first stone
Dropped: $u = 0$ , $h = 20 m$ , $g = 10 {m/s}^{2}$

$20 = 0 \cdot t + \frac{1}{2} (10) t^{2} ⟹ 20 = 5 t^{2} ⟹ t^{2} = 4 ⟹ t = 2 s$

Step 2: Time for second stone
It starts 1 second later ⇒ travel time = $2 - 1 = 1 s$

Step 3: Find initial velocity $u$

$20 = u (1) + \frac{1}{2} (10) (1)^{2} ⟹ 20 = u + 5 ⟹ u = 15 m/s$

Answer: 15 m/s

PHYSICS

A convex lens of focal length 40 cm is in contact with a concave lens of focal length 25 cm. The power of the combination in diopters is?

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

The area near an electric charge within which it exerts force on another charged particle is called ______?

بجلی کے چارج کے قریب کا علاقہ جس کے اندر یہ کسی اور چارج شدہ ذرہ پر طاقت کا استعمال کرتا ہے اسے ______ کہا جاتا ہے؟

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

A system absorbs 80 J through heating while doing 100 J of work. What is the change in the internal energy of the system?

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

An object that is moving with constant speed travels around a circular path. Which of the following is/are true concerning this motion? (i) The displacement is zero (ii) The average speed is zero (iii) The acceleration is zero

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

A light bulb has resistance of 150 Ω. Find the voltage while the current is 1.5 A?

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

Find the time period of a simple pendulum whose length is 88.2 cm. The value of acceleration due to gravity is 9.8 m/s² at the place where experiment is performed?

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

Which statement describes the electrical potential difference between two points in a wire carrying a current?

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

A 100 kg man runs up a hill through a height of 4 m in seconds. How much work does he do against gravitational force?

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

An elevator, in which a man is standing, is moving upward with a constant speed of 10 m/s. If the man drops a coin from a height of 2.5m, find the time taken by it to reach the floor of the elevator g = 9.8 m/s².

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

A body on a 20m high cliff drops a stone. One second later, he throws down another stone. Both the stones hit the ground simultaneously. Find the initial velocity of the second stone g = 10/sec².

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

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PHYSICS

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

بجلی کے چارج کے قریب کا علاقہ جس کے اندر یہ کسی اور چارج شدہ ذرہ پر طاقت کا استعمال کرتا ہے اسے ______ کہا جاتا ہے؟

اس سوال کو وضاحت کے ساتھ پڑھیں

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اس سوال کو وضاحت کے ساتھ پڑھیں

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اس سوال کو وضاحت کے ساتھ پڑھیں

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اس سوال کو وضاحت کے ساتھ پڑھیں

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اس سوال کو وضاحت کے ساتھ پڑھیں

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اس سوال کو وضاحت کے ساتھ پڑھیں

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اس سوال کو وضاحت کے ساتھ پڑھیں

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اس سوال کو وضاحت کے ساتھ پڑھیں

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