Explanation

Profit=2/100×300=6

Explanation

Given:

- Cost Price (CP) = 100  

- Profit 

Formula:

- Selling Price (SP) = CP × (1 + profit/100)

Steps:

1. Profit amount = (2/100) × 100 = 2  

2. Selling Price = CP + Profit = 100 + 2 = 102  

Explanation

We are given two equations:

Let:

• Cost of one apple = x

• Cost of one orange = y

From the problem:

1. $4x + 2y = 30$
   

2. $$x+3y=15

   
   Step 1: Solve the system of equations

Equation (1):
$4x + 2y = 30$
Divide the whole equation by 2:
→ $2x + y = 15$→ (3)

Equation (2):
$x + 3y = 15$ → (2)

Step 2: Solve equations (2) and (3)

From (3):
$y = 15 - 2x$ → (4)

Substitute (4) into (2):
$x + 3(15 - 2x) = 15$
$x + 45 - 6x = 15$
$-5x+45=15$
$-5x=15-45=-30$
$$x=−30−5=6

Explanation

Given:

• 10 lb of meat at Rs 1.69 per lb

• 20 lemons at Rs 60 per dozen

Step 1: Cost of meat

$$10 text{ lb} times 1.69 = 16.90$$

Step 2: Cost of lemons

• 1 dozen = 12 lemons

• So, price per lemon = $frac{60}{12} = 5$ Rs per lemon

• 20 lemons =$20\times 5=100$ Rs

  Step 3: Total cost

$$16.90 + 100 = 116.90$$

 Correct answer: (D) None of these

Explanation

Explanation

Year 1:

• Start: ₹12,500

• Interest: 20% of ₹12,500 = ₹2,500

• Amount due = ₹12,500 + ₹2,500 = ₹15,000

• After ₹2,000 payment: ₹15,000 - ₹2,000 = ₹13,000

Year 2:

• Start: ₹13,000

• Interest: 20% of ₹13,000 = ₹2,600

• Amount due = ₹13,000 + ₹2,600 = ₹15,600

• After ₹2,000 payment: ₹15,600 - ₹2,000 = ₹13,600

Year 3:

• Start: ₹13,600

• Interest: 20% of ₹13,600 = ₹2,720

• Amount due = ₹13,600 + ₹2,720 = ₹16,320

• After ₹2,000 payment: ₹16,320 - ₹2,000 = ₹14,320

Explanation

We use the formula for equal annual installments under compound interest:

Let the installment be Rs. x
Principal (P) = ₹2550
Rate (R) = 4% = 0.04
Time (T) = 2 years
Installments are paid at the end of each year.

Using the formula for compound installment repayment:

$$P = frac{x}{(1 + r)^1} + frac{x}{(1 + r)^2}$$

Substitute values:

$$2550 = frac{x}{1.04} + frac{x}{(1.04)^2}$$$$2550 = frac{x}{1.04} + frac{x}{1.0816}$$

Take LCM or solve directly:

$$2550=x(\frac{1}{1.04}+\frac{1}{1.0816})$$

$$2550 = x left(frac{1}{1.04} + frac{1}{1.0816} right)$$$$2550=x(0.9615+0.9246)=x(1.8861)$$

$$2550 = x (0.9615 + 0.9246) = x (1.8861)$$$$x = frac{2550}{1.8861} ≈ 1352$$

Explanation

Step 1: Define CP

Let the cost price be x.

Step 2: Selling price with 10% loss

That means:

$$\text{Initial SP}=x-10\%\text{ of }x=x-0.10x=0.90x$$

Step 3: Sale time price increases by 15%

This new selling price is:

$$\text{New SP}=0.90x+15\%\text{ of }0.90x=0.90x+0.135x=1.035x$$

We are told that this equals 54:

$$1.035x = 54$$

Step 4: Solve for x

x=54​/1.035≈52.17

Explanation

We are given:

• 35 kg of spinach costs Rs. 28

• We need to find how many kg can be bought for Rs. 16

Step 1: Find cost per kg

Cost per kg==28​/35=0.8Rs/kg

Step 2: Find how many kg for Rs. 16

$$text{Kg} = frac{16}{0.8} = 20$$0.8=20

Explanation

 Selling Price = Cost + Profit

= 1500 + (15% of 1500) = 1500 + 225 = 1725