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John is 4 years older than David and Joe is 2 years younger than David. If the sum of their ages is 41, how old will John be in 8 years ' time?
  1. 24
  2. 25
  3. 17
  4. None of these
Explanation

Let's define the ages of the three people:

  • Let David's age be
    D
    .
  • John's age is 4 years more than David's, so John's age is .
  • Joe's age is 2 years less than David's, so Joe's age is.

The sum of their ages is given as 41:

  1. Simplify the equation:


    D + D + 4 + D - 2 = 41

    3D + 2 = 41
  2. Subtract 2 from both sides:


    3D = 39
  3. Divide both sides by 3:


    D = 13

So, David is 13 years old.

  • John's age is D+4=13+4=17D + 4 = 13 + 4 = 17 years.
  • In 8 years, John's age will be:
    17 + 8 = 25 text{ years}

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اس سوال کو وضاحت کے ساتھ پڑھیں

  1. 5
  2. 6⅔
  3. 10
  4. 15
اس سوال کو وضاحت کے ساتھ پڑھیں

  1. 21
  2. 23
  3. 27
  4. 31
اس سوال کو وضاحت کے ساتھ پڑھیں

  1. 150 cm
  2. 150.24 cm
  3. 150.50 cm
  4. 151 cm
اس سوال کو وضاحت کے ساتھ پڑھیں

  1. 25
  2. 30
  3. 50
  4. 60
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