A Man Is 5 Times As Old As His Son Now. Four Years Ago, The Product Of Their Ages Was 52. What Are Their Present Ages? - Testpoint

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A man is 5 times as old as his son now. Four years ago, the product of their ages was 52. What are their present ages?

8 and 40
7 and 35
6 and 30
None of these

Explanation

The son's current age be $x$
The man's current age is 5 times the son's age, so the man's age is $5x$ .

Four years ago, the product of their age was 52.

Four years ago:

The son's age was $x - 4$ .
The man's age was $5 x - 4$ .

According to the problem, the product of their ages 4 years ago is 52:

$(x - 4) (5 x - 4) = 52$

Expand the left side:

Related MCQs

A and B invest Rs. 15,000 and Rs. 20,000, respectively, in a business. After 6 months, C invests Rs. 20,000. If the total profit after 2 years is Rs. 25,000, what is B's share of the profit?

Rs. 8,000
Rs. 9,000
Rs. 10,000
Rs. 12,000

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Explanation

Let's calculate using the capital × time method:

A: 15,000 × 24 = 360,000
B: 20,000 × 24 = 480,000
C: 20,000 × 18 = 360,000

Profit ratio = 360,000: 480,000: 360,000

Simplify:
3 : 4 : 3

Total parts = 3 + 4 + 3 = 10

B's share = $frac{4}{10} times 25,000$

= Rs. 10,000

If the number of chocolates is 20, what is one-third (1/3) of the chocolates?

5
6⅔
10
15

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There are 54 coins in total. Some are 20-cent coins and some are 50-cent coins. Their total value is $20.70. How many 20-cent coins are there

21
23
27
31

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In a class of 20 students, the average height is 150 cm. One student with a height of 155 cm joins the class. What is the new average height?

150 cm
150.24 cm
150.50 cm
151 cm

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The value of the sum of the first 4 multiples of 5 is?

25
30
50
60

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