If a sound note has intensity (I), equals to faintest audible sound (I₀), then will be it's sound level?
- 20 dB
- 10 dB
- 0 dB
- None of these
Explanation
The sound level β (in dB) is given by:
β = 10 log(I / I₀)
where I₀ is the threshold intensity (faintest audible sound). Given I = I₀:
β = 10 log(1) = 0 dB
Related MCQs
- 2x² + 4 = 9x
- 2x² + 9 = 4x
- 2x² + 9 = 4x
- x² + 4 = 9x
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