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If y ∝ 1/(x²) and y = 18 when x = 3 find y when x = 6?
  1. 4
  2. 5
  3. 6
  4. None of these
Explanation

If y ∝ 1/(x²) and y = 18 when x = 3, then y = 4.5 when x = 6

Solution:

Since y is inversely proportional to x², we can write  

y = k / x², where k is a constant.

When y = 18 and x = 3,

18 = k / 3²

18 = k / 9

k = 18 * 9 = 162

Now put k = 162 and x = 6 to find y,

y = 162 / 6²

y = 162 / 36

y = 4.5

So y = 4.5 when x = 6


Last verified on 24-05-2026

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